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Solve the following pair of linear equations by the substitution method :-S-t=3S/3+t/2=6 |
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Answer» s-t=3....1s/3 +s/2=6......2from eq 1 we get, s=3+tPutting this value of s in eq 2 .3+t/3 + t/2 = 6 6+2t+3t/6=66+5t=6×6 6+5t=36 5t =36-65t=30 t=6 now ,substituting this value of t in eq1 s-6=3 s=3 + 6s=9 Ok brthr so do.. I can do it S-t=3.......1S/3+1/2=6............2Using equation (1) we can say that S=3+tPutting in equation (2)We get3+t/3+t/2=66+2t+3t/6=65t+6=365t=30t=6Putting the value of t in equation 1We get S-6=3S=3+6S=9 Mere bhaiyo or unki bhno koi h kya kr do plz ?hey can anyone solve this ques... |
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