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Solve the following pairs of linear equation using elimination method:-3x+5y-4=0 and 9x=2y+7 |
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Answer» 3x + 5y - 4 = 0 .......... i9x - 2y - 7 = 0 ..... iimultiply ( i) by 3 and subtract ii from i\xa09x + 15y - 12 = 09x - 2y - 7 = 0+ 9x - 9x +15y - (-2y) - 12 - (-7) = 017y - 12 + 7 = 017y = 5y = 5/17subsituting the value of y in (i ) we get 3x + 5x5/17 - 4 = 0 3x + 25/17 - 4 = 03x - 43/17 = 03x = 43/17x = 43/51therefore x = 43/51 , y = 5/17 3x+5y—4=0-------(i)9x=2y+79x—2y=7------------(ii)multiplying equation (i) by 3 we get,9x+15y—12=09x+15y=12---------(iii)subtracting (iii) from(ii) we get,—2y—15y=7—12—17y=—5y={tex}5\\over17{/tex}, putting this value in (i) we get,3x+5y—4=03x+5({tex}5\\over17{/tex})—4=03x=4—{tex}25\\over17{/tex}3x={tex}68—25\\over17{/tex}3x={tex}43\\over17{/tex}x={tex}43\\over51{/tex} |
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