Solve the pair of linear equation by the substitution method. 3x-y=39x

1.	Solve the pair of linear equation by the substitution method. 3x-y=39x-3y=9
Answer» Please note given set of equations have infinte solutions ok but it is the NCERT Q Elimination by substitution :-9x-3y=9 -------> [ 1 ]\xa0Equ.3x - y = 3 ------> [ 2 ]Equ.3x = 3 + y\xa0,x = [3 + y]/ 3Put this value in equation [1 ],9\xa0× {\xa0[3 + y]/ 3 } - 3y = 9,[27+9 y ] / 3 - 3y = 9,9 [ 3 + 1 y ] / 3 = 9,3 [ 3 + 1 y ] = 9,9 + 3y = 9,3y = 9 - 9,3y = 0,y = 0,x = y + 3 / 3 = 0 + 3 / 3 = 1Hence ,x = 1 , y = 0 Naman g to solve with substitution method we must have at least 2 equation, but here both equation are equivalent to each other .

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