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Solve the quadratic equation=1/x+1 + 2/x+2 =4/x+4 |
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Answer» →1/(x+1)+2/(x+2)-4 (x+4)=0→1 [(x+2)(x+4)]+2 [(x+1)(x+4)]-4[(x+1)(x+2)]=0→(X)^2+4x+2x+8+2(x)^2+8x+2x+8-4 (x)^2-8x-4x-8=0→- (x)^2+4x-8=0→(x)^2-4x+8 =0 -1x=1x²( not sure about it ) X=-1 or X=14 |
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