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| 1. |
Solve the quadratic equation:-16/x -1=15/x+1 |
| Answer» We have {tex}\\frac{{16}}{x} - 1 = \\frac{{15}}{{x + 1}}{/tex}{tex} \\Rightarrow \\frac { 16 - x } { x } = \\frac { 15 } { x + 1 }{/tex}Cross multiply,{tex}\\Rightarrow{/tex}\xa0{tex}(16-x)(x+1)=15x{/tex}{tex} \\Rightarrow{/tex}\xa0{tex}16x+16-x^2-x=15x{/tex}{tex} \\Rightarrow{/tex} 15x - 16x - 16 + x2 + x = 0{tex} \\Rightarrow{/tex} x2 - 16 = 0{tex} \\Rightarrow{/tex} x2 = 16{tex} \\therefore{/tex} x = {tex} \\pm{/tex}4 | |