solve x: 1÷(a+b+c)=1÷a+1÷b+1÷x, [a,b,x is not equal to0, x is not equal to-(a+b)]

solve x: 1÷(a+b+c)=1÷a+1÷b+1÷x, [a,b,x is not equal to0, x is not

1.	solve x: 1÷(a+b+c)=1÷a+1÷b+1÷x, [a,b,x is not equal to0, x is not equal to-(a+b)]
Answer» 1/(a+b+x) - 1/x = 1/a + 1/b => -(a+b)/x(a+b+x) = (a+b)/ab. Cancel (a+b) from both sides & cross multiply=> -ab = x(x+a+b) => x^2+(a+b)x+ab = 0=> (x+a)(x+b) = 0x = -a or -b Ans