1.

solve: x/2 +2y/3 =11 and x-y/4 =3

Answer» First make two linear equations 3x+4y=66 take it as eq1 (solve that same as like fractions )3×x+2y×2/6=11 Next eq no2 4x-y=12 4×x-y×1/4=3 Solve the two eqs 3x+4y=66 and 4x-y=12 multiply 4 for 1st eq and add to balance coeffiecient of y So we get x=6 and y=12


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