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State and prove area of similar triangle theorem |
| Answer» Given\xa0:∆ABC ~ ∆PQRRTP:Construction:Draw AM perpendicular to BC and PN perpendicular to QR.Proof:∆ABM~∆PQN ( By AA similarity )Also ∆ABC ~ ∆PQR (given)\xa0\\* From (1),(2) and (3)Now, by using (3) , we get | |