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State whether the matrix \(\begin{bmatrix}2 & 3 \\6 & 4 \\\end{bmatrix}\) is singular or non-singular. |
Answer» Let A = \(\begin{bmatrix} 2 & 3 \\ 6 & 4 \\ \end{bmatrix}\) Then |A| = \(\begin{bmatrix} 2 & 3 \\ 6 & 4 \\ \end{bmatrix}\) = 2 × 4 - 3 × 6 = -10 (Expanding along R1) Since |A| ≠ 0, therefore A is a non-singular matrix. |
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