1.

State whether the matrix \(\begin{bmatrix}2 & 3 \\6 & 4 \\\end{bmatrix}\) is singular or non-singular.

Answer»

Let A = \(\begin{bmatrix} 2 & 3 \\ 6 & 4 \\ \end{bmatrix}\)

Then |A| = \(\begin{bmatrix} 2 & 3 \\ 6 & 4 \\ \end{bmatrix}\)

= 2 × 4 - 3 × 6

= -10 (Expanding along R1)

Since |A| ≠ 0, therefore A is a non-singular matrix.



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