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Statement-1: If f and g are differentiable at x=c, then min (f,g) is differentiable at x=c. Statement-2: min (f,g) is differentiable at `x=c if f(c ) ne g(c )`A. 1B. 2C. 3D. 4 |
Answer» Correct Answer - D Let f(x)=x nd g(x)=`x^(2)` then, `min (f(x),g(x))={{:(,x,x lt 0),(,x^(2),0 le x lt 1):}` Clearly, f(x) and g(X) are differentiable at x=0. But, min [f(x),g(x)] is not differentiable at x=0. So, statement-1 is not true. However, statement-2 is true. |
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