Sum of all exterior angle of a hexagon is 360 degree

1.	Sum of all exterior angle of a hexagon is 360 degree
Answer» We know, the sum of all exterior angles of a pentagon is 360°Therefore, (m + 5)° + (2m + 3)° + (3m + 2)° + (4m + 1)° + (5m + 4)° = 360°⇒ m + 5 + 2m + 3 + 3m + 2 + 4m + 1 + 5m + 4 = 360°⇒ 15m + 15 = 360°⇒ 15m = 360° - 15°⇒ 15m = 345°⇒ m = 345°/15°⇒ m = 23°Therefore, the first angle = m + 5°= 23° + 5°= 28°Second angle = 2m + 3°= 2° × 23° + 3°= 46° + 3°= 49°Third angle = 3m + 2= 3° × 23° + 2°= 69° + 2°= 71°Fourth angle = 4m + 1= 4° × 23° + 1°= 92° +1°= 93°Fifth angle = 5m + 4°= 5° × 23° + 4°= 115° + 4°= 119°

Discussion