Sum of first n natural numbers=n(n+1)/2

1.	Sum of first n natural numbers=n(n+1)/2
Answer» sñ =1+2+3+4......+ñsñ=ñ/2[2(1)+[ñ-1)1]=ñ(ñ+1)/2 meet.google.com/vkd-rwgd-dbx join this link Sn= 1+2+3+4+5+........+nSn =n/2(2(1)+(n-1) 1)= n(n+1)/2

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