Sum of four consecutive terms of an AP is 50 and fourth term is four times the first find the AP

Sum of four consecutive terms of an AP is 50 and fourth term is four t

1.	Sum of four consecutive terms of an AP is 50 and fourth term is four times the first find the AP
Answer» Let the 4 numbers are a , a + d , a + 2d , a + 3d.Sum of 4 numbers AP = 50a + a + d + a + 2d + a + 3d = 50⇒ 4a + 6d = 50⇒ 2a + 3d = 25 --------------(1)Also given the forth term is four times the first4(a) = a + 3d4a - a = 3da = dputting a = d in (1) , we obtain5d = 25d = 5a = 5 but d = a.∴ First four terms are 5 , 10 ,15 , 20.\xa0