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| 1. |
Sun 60 cos 30 +sin 30 cod 60 |
| Answer» We\xa0have{tex}\\sin 60^\\circ\\cos 30^\\circ + \\cos 60^\\circ \\sin 30^\\circ {/tex}{tex} = \\frac{{\\sqrt 3 }}{2} \\times \\frac{{\\sqrt 3 }}{2} + \\frac{1}{2} \\times \\frac{1}{2}{/tex}{tex} = \\frac{3}{4} + \\frac{1}{4}{/tex}{tex} = \\frac{{3 + 1}}{4}{/tex}{tex} = \\frac{4}{4}{/tex} =1 | |