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Suppose that a certain semiconductor memory chip has a capacity of 8K × 8. How many bytes could be stored in this device?(a) 8,000(b) 65,536(c) 8,192(d) 64,000I got this question in an interview.This question is from Erasable Programmable Read Only Memory in section Memory Devices of Digital Circuits

Answer»

The CORRECT option is (C) 8,192

Easiest EXPLANATION: 8K = 8 * 1024 = 8192.



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