t²-15 Que. From polynomials

1.	t²-15 Que. From polynomials
Answer» By comparing the given poly. with ax^2 + bx + c =0,we geta = 1, b=0, c=-15We have, t^2-15=0 t=+_√15Therefore, the zeroes of the polynomial t^2-√15 are √15,-√15Now, sum of zeroes=-b/a √15 - √15= -0/1 0=0 Also, product of zeroes=c/a√15 × (-√15) = 15/1 15 = 15 Hence, Verified

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