1.

tan (19π/6) =____________________(a) √3(b) -1/√3(c) – √3(d) 1/√3I had been asked this question in an online interview.Question is from Trigonometric Functions in section Trigonometric Functions of Mathematics – Class 11

Answer»

The CORRECT ANSWER is (d) 1/√3

To EXPLAIN I WOULD SAY: tan (19π/6) = tan (2π + 7π/6) = tan 7π/6 {tan( 2nπ+x)=tan x}

= tan (π+π/6) = tan π/6 = 1/√3. {tan π+x = tan x}



Discussion

No Comment Found

Related InterviewSolutions