Tan 2A=cot(A-18°) where 2A is an acute angle ,find the value of A

1.	Tan 2A=cot(A-18°) where 2A is an acute angle ,find the value of A
Answer» We have, tan 2A = cot (A - 18°){tex}\\Rightarrow{/tex}\xa0tan 2A = tan {90° -(A -18°)}{tex}\\Rightarrow{/tex}\xa0tan 2A = tan (108° - A){tex}\\Rightarrow{/tex}\xa02A = 108° - A{tex}\\Rightarrow{/tex}\xa03A = 108°{tex}\\Rightarrow{/tex}\xa0A = 36° Thank you so much

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