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| 1. |
Tan^2A/sec^2A-1=? Please and this. |
| Answer» {tex}tan^2A\\over sec^2A-1{/tex}=\xa0{tex}sec^2A-1\\over sec^2A-1{/tex}\xa0as\xa0{tex}sec^2\\theta -tan^2\\theta = 1{/tex}= 1 | |