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tan(75°) =___________________(a) 2+\(\sqrt{3}\)(b) 2-\(\sqrt{3}\)(c) 1+\(\sqrt{3}\)(d) \(\sqrt{3}\)-1The question was posed to me in homework.My enquiry is from Trigonometric Functions of Sum and Difference of Two Angles-1 in chapter Trigonometric Functions of Mathematics – Class 11 |
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Answer» RIGHT choice is (a) 2+\(\sqrt{3}\) BEST EXPLANATION: tan (X +y) = (tan x + tan y)/(1- tan x tan y) tan (45°+30°) = (tan 45° + tan 30°)/(1- tan 45° tan 30°) tan 75° = (1+ 1/\(\sqrt{3}\))/(1-1/\(\sqrt{3}\)) = (\(\sqrt{3}\) + 1)/ (\(\sqrt{3}\) – 1) = 2+\(\sqrt{3}\). |
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