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Tan A = 3/4, find the value of 1/sinA + 1/cos A |
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Answer» J Tan = P/BWhere P = 3 and B = 4For hypotenuseBy Pythagoras theoremH×H = P×P + B×B = 3×3 + 4×4 = 9 + 16 = 25 H = 51/SinA = CosecA1/CosA = SecACosecA = H/P and SecA = H/BCosecA + SecA = 5/3 + 5/4 = 20 +15/12 = 35/12 25/12 Can you explain the answer 1/3/5+1/4/5 |
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