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Tan A=4/3 and a is acute then sin a is |
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Answer» Sin a is equal to 4/5 Tan A=4/3 and a is acute then sin a is tanA=4/3=p/b. Here,p=4 and b=3 By Pythagoras theorm, h^2 =p^2 + b^2 . =4^2 + 3^2 =16 + 9 = 25 h= 5 ( 5^2 = 25 ) now sin A = p/h sin A = 4/5 |
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