Tan(A+B)=√3, tan (A-B)=1/√3,

1.	Tan(A+B)=√3, tan (A-B)=1/√3,
Answer» Tan (A +B)=root 3=(A+B)=60 (1)TAN (A_B)=1/ROOT 3=(A_B)=30 (2)solving 1 and 2 we get2a=90A=45degree. Put the value of a in eq (1) 45+b=60B=15degree Tan( A+B ) = √3. A+B = 60⁰ - (i) (∵tan 60⁰= √3) tan (A-B)=1/√3. A-B = 30⁰ -(ii) (∵tan 30⁰ = 1/√3) Add equation (i) and (ii) (A+B=60⁰) + ( A-B = 30⁰) 2A = 90⁰ A = 90⁰/2 A = 45⁰ Put A = 45⁰ in equation (i) A + B = 60⁰ 45⁰ + B = 60⁰ B = 60⁰ - 45⁰ B = 15⁰

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