InterviewSolution
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InterviewSolution
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tan A + sec A -1÷tan A-secA+1=1+sinA÷cosA |
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Answer» Proof:LHS=(tanA +secA) - (sec2A - tan2A) / tanA + 1 - secA as sec2A - tan2A=1=(tanA+ secA) (1 - (secA - tanA))/tanA + 1 - secA=(tanA +secA) (1 - secA + tanA) /\xa0(1 - secA+tanA )=sec A + tan A=1/cosA + sinA/cosA\xa0=(1 + sinA) / cosA =RHS\xa0\xa0 It is in this app itself. It is in the exercise 8.3 of exemplar problems of chapter intro to trigonometry Prove this |
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