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| 1. |
tan square theta minus sin square theta |
| Answer» tan2θ– sin2θ{tex} = {\\tan ^2}\\theta - \\frac{{{{\\sin }^2}\\theta }}{{{{\\cos }^2}\\theta }} \\cdot {\\cos ^2}\\theta \\left[ {\\because {{\\tan }^2}\\theta = \\frac{{{{\\sin }^2}\\theta }}{{{{\\cos }^2}\\theta }}} \\right]{/tex}= tan2θ– tan2θcos2θ= tan2θ(1 – cos2θ) {tex}\\left[ \\because \\sin ^ { 2 } \\theta = 1 - \\cos ^ { 2 } \\theta \\right]{/tex} | |