1.

Tan tetha = 8/15 ,if PQ=16 cm,then the length of PR is

Answer» taking x instead of titatan x = 8/15tan x = PQ/QRPQ/QR =8/1516/QR = 8/1516 x 15/8=QRtherefore ,QR = 30 mPQ2\xa0+ QR2\xa0=PR2162\xa0+ 302\xa0= PR2256 + 900= PR21156=PR2PR= root 1156PR = 34 m


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