1.

Tan theta/(sec theta-1)+Tan theta /(sec theta +1) =2cos theta

Answer» LHS ={(Sec theta +1)*tan theta + ( sec theta -1)*tan theta}/ (sec sq. theta -1) ={Tan theta (sec theta+1+sec theta-1)}/(tan theta*tan theta)=(2sec theta)/ tan theta =2Cosec theta =RHS=2 cosec theta =LHS=RHS: Hence proved


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