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| 1. |
Tan4A+tan2A=sec4A-sec2A |
| Answer» Explanation: Use one of the Pythagorean identity namely,sec2A=1+tan2A\xa0sec4A−sec2A=(sec2A)2−sec2A=(1+tan2A)2−(1+tan2A)=1+2tan2A+tan4A−1−tan2A=tan4A+tan2A | |