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| 1. |
TanA\\secA-1+tanA\\secA+1=2cosecA |
| Answer» LHS=TanA\\secA-1+tanA\\secA+1=tanA(secA+1)+tanA(secA-1)\\(secA-1)(secA+1)=tanA[secA+1+secA-1]\\sec^2 - 1=tanA(2secA)\\tan^2A (sec^2A - 1=tan^2 A) =2secA \\tanA=2cosecA | |