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TanQ/1-cotQ + cotQ/1-tanQ = 1+ tanQ + cotQ |
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Answer» Free fire uid - 1099673223 $$ L H S ==1−tanxcotx\u200b+1−cotxtanx\u200b1−tanxcotx\u200b+(1−cotx)(−tanx)tanx(−tanx)\u200b1−tanxcotx\u200b−1−tanxtan2x\u200b1−tanxcotx−tan2x\u200b=tanx(1−tanx)1−tan3x\u200b(1−tanx)(tanx)(1−tanx)(1+tanx+tan2x)\u200b1+cotx+tanx=\xa0R H S\xa0Hence proved. |
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