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{tex}2√3x²-5x+√3{/tex}

Answer» {tex}2\\sqrt 3x^2-5x+\\sqrt 3 =0{/tex}{tex}=> 2\\sqrt 3x^2-3x-2x+\\sqrt 3 =0{/tex}{tex}=> \\sqrt 3x(2x-\\sqrt 3)-1(2x-\\sqrt 3) =0 {/tex}{tex}=>( \\sqrt 3x-1)(2x-\\sqrt 3) =0 {/tex}{tex}=>x= {1\\over \\sqrt 3},{\\sqrt 3\\over 2} {/tex}


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