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The 10th and 18th term of AP are 41&73 respiculty find 26th term

Answer» a10 = 41, a18 =73 and a26 =?a10= a + 9d = 41-------(1)a18= a + 17d=73-------(2) (-). (+). (-) ----------------------- -8d = -32 d=4Put d=4 in eqn.(1)a+9d=41 a+9(4)=41 a+36=41 a=5Therefore, a26= a+25d = 5+25(4) = 5+100 a26= 105
a26=105
10th term of AP is 41= a+9d=41---(1)18th term of AP is 73=a+17d=73----(2)Solve (1)&(2);a+9d=41 a+17d=73 ------------------ -8d=-32d=4,substitute d= 4in (1)a+9(4)=41a=5So a26=a+25d =5+100=105


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