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| 1. |
The 17th of an ap exceed it 10th by 7 .find the common difference. |
| Answer» Let the first term and the common difference of the AP be a and d respectively.Given that, a17 = a10+7\xa0{tex} \\Rightarrow {/tex}\xa0a + (17 - 1) d = a + (10 - 1)d + 7\xa0{tex}\\because {/tex}an = a +(n - 1)d{tex} \\Rightarrow {/tex}\xa0a + 16d = a + 9d + 7{tex} \\Rightarrow {/tex}\xa016d - 9d = 7{tex} \\Rightarrow {/tex}\xa07d = 7{tex} \\Rightarrow d = \\frac{7}{7} = 1{/tex}Hence, the common difference is 1. | |