1.

The 17th term of an ap exceeds its 10th term by .7 find the common difference

Answer» 7
a +(17-1)d=a+(10-1)d+7a+16d=a+9d+7a-a+16d-9d=77d=7d=7/7d=1
d =1
7d= 7
a+16d = a+9d + 7


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