1.

The 19th term of an AP is equal to three times its sixth term.if its 9th term is 19,find the AP

Answer»
Let a be the first term and d be the common difference of the AP. Then,

a19=3(a6)a9=19a+8d=19a=19-8d .......(1) a19=3(a6)a+18d=3(a+5d)a+18d=3a+15d18d-15d=3a-a3d=2a3d=2(19-8d) ........(from 1)3d=38-16d3d+16d=3819d=38d=38/2d=2. ......(2)Put d=2 in eq.1a=19-8×2a=3now put values of a &d in above equationa19=3(a6)a+18d=3(a+5d)3+18×2=3(3+5×2)3+36=3(3+10)39=9+3039=39 .•. AP= 3,5,7......H.P.Hope this helps.?Regards


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