1.

The 24th rerm of an A.P. is twice its 10th term. Show that its 72nd term is 4 time its 15th term

Answer» a+23d=2a+18da=5d(23d-18d=5d) (i)a15=5d +14d (from i ) a15=19d (ii)now,a72=5d+71d (from i ) a72=76da72=4(19d)a72=4a15H.P.
a24\xa0= 2a10a+23 d= 2(a+9d)a+23d = 2a+18d23d-18 d= 2a-a5d= aa72 =\xa04a15a+71d = 4(a+14d)5d+71 d= 4a+56d76d= 4(5d)+56d76 d= 20d+56d76d=76dhence proved


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