1.

The 4 th term of an AP is 0.prove that the 25th term of an AP is 3 times its 11th term.

Answer» a+3d=0 (eq..1) given, a=-3d.(eq 2)Now ,A+24d=3(a+10d) to prove.. Substitute value of a, -3d+24d=-9d+30 , 21d=21d .. Therefore proved.. NOT SURE SO PLEASE ANY TEACHER CHECK MY WAY.
Anusree r u a malayali
it has been given that a4=0 => a+3d=0 => a= -3d ------- (1)a11= a+10d = -3d+10d = 7d [ from (1)]a25 = a+24d = -3d+24d = 21d [ from (1)]therefore, comparing 7d and 21d we get, 21d = 3 ( 7d ) i.e. a25 = 3(a11) Hence, proved.Hope it helps.


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