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The 6th term of an AP is zero. Prove that it\'s 31st term is five times the 11th term. |
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Answer» 31st term is a + (31-1)da + 30d..........(1)....... 11 th term is a +(11-1)da + 10dso 5 times 11 term is5a + 50d.........(2)...... so 5 times 11 term is5a + 50d.........(2)......on comparing with 1 a + 4a + 50das a = -5da + 4(-5d) + 50da - 20d + 50da + 30d31st term.... pehle vala answer mt dekho.... ye apka solution hai Ek kam kijiye put a6 = 0, ---> a+5d=0..., (a=5d), ab find a31 and a11...... ▪a31= a+30d ....... ▪a31=5d +30d = 35 d........ and a11=a+10d ▪a11=5d +10d =15d...... Pehle 31st trm nikalo phir 11th trm. Nikalo aur uske baad a=-5d put ksr dena Hey, its proved bt yahan solition thoda bada hai, apko kaise dun mai |
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