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| 1. |
The 7th and 3rd term is an ap is 12 and 5 find the 13th term |
| Answer» 7th term of ap = a+6d .. (1),3rd term of ap=a+2d .. (2),Subtracting (2) from (1), a + 6d =12-a - 2d = -5--------------------4d =7d=7÷4,a=12-6d, 12-6×7÷4,a=3÷2 Now, 13th term of ap=45÷2 | |