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| 1. |
The 7th term of an AP is _4 and its 13th term is_ 16 find AP |
| Answer» a7=4a+6d=4.........[1]a13=16a+12d=16......[2][2]-[1]6d=12d=12/6d=2Substituting d=2 in [1]a+6d=4a+12=4a=-8Therefore,AP= -8,-6,-4,-2,0,2,4,6,8,10,12,14,16,..... | |