The 8th term of an AP is half of its second term exceeds one third of its fourth by 1.find

The 8th term of an AP is half of its second term exceeds one third of

1.	The 8th term of an AP is half of its second term exceeds one third of its fourth by 1.find
Answer» a+7d=a+d/22a + 14d = a + da = -13da +10d = 1/3(a +3d) + 1a +10d -1 = 1/3(a + 3d)3(a + 10d -1) = a +3d3a + 30d -3 = a+ 3d2a + 27d =3 2(-13d) + 27d =3(since a = -13d)-26d + 27d = 3 d = 3a= -13d a = -39a + 14d = -39 + 42 hence a15 =3