The acceleration due to gravity on the planet `A` is `9` times the acceleration due to gravity on planet `B`. A man jumps to a height of `2 m` on the surface of `A`. What is the height of jump by the same person on the planet `B` ?A. 18 mB. 6 mC. `(2)/(3) m`D. `(2)/(9) m`

The acceleration due to gravity on the planet `A` is `9` times the acc

1.	The acceleration due to gravity on the planet `A` is `9` times the acceleration due to gravity on planet `B`. A man jumps to a height of `2 m` on the surface of `A`. What is the height of jump by the same person on the planet `B` ?A. 18 mB. 6 mC. `(2)/(3) m`D. `(2)/(9) m`
Answer» Correct Answer - A `H_(max) = (u^2)/(2 g) rArr H_(max) prop (1)/(g)` On planet `B` value of `g` is `1//9` times to that of `A`. So value of `H_(max)` will become `9` times, i.e., `2 xx 9 = 18` metre.

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The acceleration due to gravity on the planet `A` is `9` times the acceleration due to gravity on planet `B`. A man jumps to a height of `2 m` on the surface of `A`. What is the height of jump by the same person on the planet `B` ?A. 18 mB. 6 mC. `(2)/(3) m`D. `(2)/(9) m`

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