1.

The accepted value for the density of gold metal is 19.31 g/cm^3. If a student measured the mass and volume of a sample of gold, and obtained a value of 19.03 g/cm^3, the percent difference would be ______(a) -1.5%(b) 1.5%(c) -0.5%(d) 0.5%The question was asked in quiz.This question is from Errors in Data and Calculations topic in chapter Presentation and Analysis of Data of Bioprocess Engineering

Answer»

Correct answer is (a) -1.5%

To ELABORATE: % DIFFERENCE = [(19.03 – 19.31) G/19.31 g] x 100% = – 1.5%

A percent difference can be POSITIVE or negative; the sign shows whether the experimental value is HIGHER or lower than the actual or theoretical value. This distinction is not used in precision since all values are experimental.



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