1.

The amount of alcohol in two varieties of whiskey are 27% volume/volume and 42% volume/volume. In what ratio should they be mixed so that the mixture has 33% volume/volume alcohol?1). 8 : 72). 3 : 23). 2 : 14). 1 : 1

Answer»

Let the whiskeys are mixed in AMOUNTS M litres and N litres.

⇒ Amount of alcohol in first VARIETY = 0.27M

⇒ Amount of alcohol in second variety = 0.42N

Total amount of mixture = (M + N) litres

Amount of alcohol in mixture = 33% volume/volume = 0.33(M + N)

⇒ 0.27M + 0.42N = 0.33(M + N)

⇒ 0.09N = 0.06M

⇒ M/N = 3/2

RATIO in which they should be mixed is 3 : 2.


Discussion

No Comment Found

Related InterviewSolutions