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The angle of elevation is 60°on site of tower find the height of tower on the ground level is 10m. |
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Answer» Tan Q=p/b, tan 60=p/10 root 3 =p/10 10×root 3=p p=10 root 3 it\'s a answer 10 underroot 3m Tan30° = √3 Let the height be h so h/10 = √3 & h= 10√3 m |
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