The area of a rectangle is 192cm2 and it\'s perimeter is 56cm. Find the diameter of rectangle.

The area of a rectangle is 192cm2 and it\'s perimeter is 56cm. Find th

1.	The area of a rectangle is 192cm2 and it\'s perimeter is 56cm. Find the diameter of rectangle.
Answer» Area of rectangle = length x breadth192 = l xb\xa0perimeter = 2(length+ breadth)56= 2(l+b)(l+b)= 56/2 =28l = 28-bSubstituting the value of l in eq(1), we get(28-b) x b = 19228 b-{tex}b^2{/tex}\xa0= 192{tex}b^2-28b +192 = 0{/tex}{tex}b^2-16b-12b+192= 0{/tex}b(b-16)-12(b-16) = 0(b-12)(b-16)= 0b=12 or 16If b= 12 then l=16{tex}Diagonal = (l^2+b^2)^1/2{/tex}Diagonal = ({tex}16^2+12^2)^1/2{/tex}diagonal = (256+144){tex}^1/2{/tex}Diagonal = ({tex}400)^1/2{/tex}Diagonal = 20 cm\xa0