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The area of the region bounded by `y=sinx`, `y=cosx` in the first quadrant is |
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Answer» Area=`int_0^(pi/4) sinxdx+int_(pi/4)^(pi/2) cosxdx` `=(cosx)_0^(pi/4)+(sinx)_(pi/4)^(pi/2)` `=1-cospi/4+sinpi/2-sinpi/4` `1-1/sqrt2+1-1/sqrt2=2-sqrt2` option d is correct. |
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