The area of the sector is _____(a) \(\frac {x^{\circ }}{360^{\circ }}\) × πr^2(b) \(\frac {x^{\circ }}{360^{\circ }}\) – πr^2(c) \(\frac {x^{\circ }}{360^{\circ }}\) + πr^3(d) \(\frac {x^{\circ }}{360^{\circ }}\) × πr^3This question was posed to me in an internship interview.The above asked question is from Number of Tangents from a Point on the Circle topic in portion Circles of Mathematics – Class 10

The area of the sector is _____(a) \(\frac {x^{\circ }}{360^{\circ }}\

1.	The area of the sector is _____(a) \(\frac {x^{\circ }}{360^{\circ }}\) × πr^2(b) \(\frac {x^{\circ }}{360^{\circ }}\) – πr^2(c) \(\frac {x^{\circ }}{360^{\circ }}\) + πr^3(d) \(\frac {x^{\circ }}{360^{\circ }}\) × πr^3This question was posed to me in an internship interview.The above asked question is from Number of Tangents from a Point on the Circle topic in portion Circles of Mathematics – Class 10
Answer» RIGHT answer is (a) \(\frac {x^{\circ }}{360^{\circ }}\) × πr^2 Explanation: The AREA of the SECTOR is \(\frac {x^{\circ }}{360^{\circ }}\) × πr^2 Where x° is the DEGREE measure of the angle at the center and r is the radius of the circle.

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