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The common tangents AB and CD to two circles O and O\' intersecct at E . Prove that AB =CD.\xa0

Answer» It isEA\xa0and EC are the tangents of circle with centre O soEA=EC (Tangents drawn from the external point of circle are equal)-1NowSimilarly,ED and EB are the tangents of circle with centre O\' soEB=ED (Tangents drawn from external point of circle are equal)-2Adding 1 and 2EA+EB=EC+EDAB=CD


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