The difference of two natural no. Is 5. If the difference in their reciprocal is 1/10. Find the no.

The difference of two natural no. Is 5. If the difference in their rec

1.	The difference of two natural no. Is 5. If the difference in their reciprocal is 1/10. Find the no.
Answer» Let two numbers be x and y. So x-y= 5 ...(1)1/y-1/x= 1/10x-y/xy = 1/105/xy = 1/10xy = 50From eq (1), we have x= 5+y(5+y)y = 50y2+5y = 50y2\xa0+5y -50=0y2\xa0+10y -5y -50=0y(y+10) -5(y+10) =0(y+10)(y-5) = 0y = 5 or -10y= 5 because -10 can not be a natural numberx = 5+5 =10One number is 5 and other number is 10.\xa0